Kakuro Puzzles

Possibilities, orphans and a chain.

Just orphans. 12 numbers without them and then stuck.

Straightforward nada

Slarti +1

stuck half way thru, curious to know how Slartibartfast did it

first 12 easy. then you have to count 7's. turns out 26A has to have a 7 therefore it's 4679. ta-da

Solution...
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Solve bottom right. Restrictions for A lead to filling in A, E, & D. Then can fill rest of A-G.
Bottom 2 of 21D are 56 so middle 2 are 34. Counting 7s forces J to be 3, and N is then 4. Since 26A needs a 7 it is 4679 in some order.
That forces 5 to bottom of 29D, from there it's easy.

nada, isolate the 5 on 29D

-o-p but too many starts for nada

My approach started off similar to Dan's, but didn't count the 7's. After first 10 cells, R, V must be 5 or 6, S must be 8 or 9, so W cannot be 8 or 9. Must be 5. Obvious from there.

6:32. Counting 7's was key.

yup, after the first 13 easy ones, either count 7s or consider that
27A != 4689 while
26A != 3689 else breach of unique rule.

Disastrous for me - what does counting 7s mean?

Anne - when stuck, a good technique is to see how many of a certain digit must be in the acrosses and how many more might be, and compare to the downs. In this puzzle the 7 had been placed in Z, and after filling in the top row you can see that 29D, 27D, and 39D each need a 7 which means that all 3 of 15A, 27A, and 26A need a 7 in them since there are no other possible acrosses.

Used possibilities

+p+o

4:17

Forgot the timer!