Kakuro Puzzles

does this need a chain?

used orphan and chain

used what seemed right without being 100 percent sure and it worked fine.got lucky

Same here. Used orphans and guessed on a chain and it worked out.

Ugh, chains.

couldn't do it with logic. resorted to guessing chains

Used orphans, no chains. Think maybe orphans are not needed but I'm not gonna figure it out.

Key for me was to study the 3's and concluding that 18A, 15A and 19A as well as 22D, 10D and 24D all had to have 3's which eliminated 3's from C, X and Z (can't remember if it eliminated more). Anyway...that helped update possibilities and then orphans made it an easy solution to the end.

'Me from here''s strategy with 3's did not work for me, because 18A, 19A and 15A all have solutions without 3's that I cannot eliminate with logic.

I agree with Mike. 3's didn't help. Orphans and chains.

re-read my comment - not clear on what logic was applied. doh!

All solutions to 22D, 10D and 24D require 3's, but only 18A, 26A, and 19A have 3's to satisfy this requirement. That means 18A, 26A and 19A have to have 3's.

Note 26A has no 3's (N=57, O=24, P=689, Q=689).

Crap. 18A, 15A and 19A are ones that have 3's, therefore must have 3's because 22D, 10D and 24D need them.

26A is as noted.

OK. I redid the puzzle using Me's logic and it helped a lot. I understand his logic, the only piece I didn't spend the time to check was that 24D needed a 3. Given that the minimum of two of the cells is 11, making 13 or less with 4 cells probably needs a 3. I just didn't spend the time to confirm that.

yup, good logic solution from 'me from here'. Needs orphans. And quite a bit of work too.

I went back and looked at Me's 3's logic. Brilliant solution. Quite simple solution with orphans after that. Probably possible w/out orphans, but I've spent enough time on this puzzle.

Nope, even with orphans and me's 3s clue, still stuck, 2019

What a great puzzle with orphans. After the 3 trick focus on eliminations for 19A. Since it has to contain 3, it cannot start with a 7 (cause the orphan can only be any of 4578 and we need to place 1236). Then proove that 19 has to include 2 (no way to place 13456). Next, eliminate 4 from the entire 19 (that would require placing a 9, but that's obvioisly impossible). Then it all falls into place.