Kakuro Puzzles

3:31

nada, not quite, but almost, maybe it is ...
after first six easy ones ...
27A has at least two of 6789, which locates the 7 in 22A and the 6 in 39D.
27A=xxx456x, 45 pair at end of 22A and 15D!=xxx9 and 27A must have a 3, solves.

Easy with possibilities and orphans.

Nada with a couple of restarts so not really nada.

1:50

nada

Aspie: Try as I might, I don't see six easy ones (unless you use orphans, as I did).

Aspie: Oh! I bet you used the unique rule.

+P

nada but tough

Wilo, yes after DEFG I used unique rule:
1. KQ is 12 pair, so HN is not
2. HN must be 23 pair (solves AB)

Willo, yes, solves 10A. I allow unique rule if no other way to make progress.
Uniqueness is a rule of the creation process. At its most simple, Puzzle creator makes a grid, randomly populates it (well no same number in row or column) calculates the Across and Down sums, and then sets out to More...

Nada

Nada, but very tough. I used the unique rule early to conclude that B=9. Aspie, I see no reason to make uniqueness a last resort. It's as true and valuable as using crosses and all the other little tricks we have.

To me, the implicit challenge of these puzzles is to find **all** solutions, not **a** solution. It's clear that the solutions are all unique, but I take that to be a quirk of the puzzle-setter, similar to a quirk where the bottom right entry is always a 7. I prefer not to take advantage of that quirk. To each his/her own, of course.

I have seen too many published Kakuro/Sudoku puzzles, even those with cash prizes, with multiple solutions. Assuming a unique solution is the same as guessing. You have to be lucky that the programmer that generated the puzzle knew what they were doing. Just because all the puzzles you have seen on this web-site so far have a unique solution is not proof that all of them are unique.

I must have made a mistake or assumption somewhere? I found this one straightforward with a bit of thought, no uniqueness or orphans needed?