Kakuro Puzzles

-o+c

+o+c

Calculated helpful orphans then slogged through a lot of chains using possibilities to keep track of the process of elimination. Inelegant puzzle.

+p+o. I worked it like Plum.

18:40. Took a lot of thought.

Nada. I thought it was very elegant.

my only chain eliminated E=5. Mike, how did you do nada?

+P

My nada approach: A&B must be 1,2 or 3. C is 1 or 2. So D=4 & E=5, which means O=1, P=2. So 13=256 (274 is no good because you need the 4 elsewhere.) Then look at the lowest possible value for each of the cells in 29D, which is helped by looking at what 11D can be. You can figure out what F is and that tells you Q=4. Keep looking at 29D and it all falls into place.

Sorry, I meant V=4, not Q.

+p+o+c. Not fun.

+o+p
Mike, How did you eliminate 5 from A?

from what I can tell, chain eliminates A=5: 11D=542, BC is 12 pair, 10D=37, 8D=26 (but can't solve 29D). Mike, did you find something simpler?

Jimmy - I figured out that F cannot be 4. If F is 6, 7 or 8, so that eliminates A=5. Can't recall how I decided F > 4 w/o doing it all over again.

Don, no it wasn't simpler. I looked at it from the standpoint of what works in 29D. If A=5, then 11D is 542, which makes L=9, so then G and H are 76 pairs, which makes I=9 or 8, which makes D= 1 or 2, which can't be.

ok, thanks Mike & Don

13:50