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Kakuro Kakuro
How to play Kakuro
Kakuro is similar to both sudoku and traditional crossword games.
Like a Crossword
Similar to crosswords, Kakuro has clues both across and down. When you put numbers in the vacant squares, the sum must equal the given clues. This is why the game is sometimes called 'cross sums'.
Like a Sudoku
Just like a sudoku, you cannot have the same number in a row or column. If a row is broken into 2 areas by a clue, then you can have the same number occuring once in each of the separate areas.
Other variations
Still looking for more puzzles? How about a variation on sudoku? Try Wordoku. Wordoku uses letters instead of numbers and has a hidden 9-letter word! For crossword puzzles, try Free Crossword PUzzles. 2 free crosswords (Easy, Hard) daily.

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Hard Kakuro for 30/December/2017


 
  
 24 
  
 17 
  
 21 
  
 39 
    
  25
  
        
  
 17 
  
  32
  
            
   
  20
 17 
      
  
 17 
 
  21
  
      
  
 17 
  
 
  33
  
          
   
  23
  
        
Choose a number, and place it in the grid above.
  1 2 3 4 5 6 7 8 9
Talk about anything and everything, but nice to each other - you don't have to agree, but this is not the place for personal attacks. As Sir Paul McCartney said: 'I used to think anyone doing anything weird was weird. Now I know that it is the people that call others weird that are weird' (longer explanation). Enjoy!
Paul  From The oldest town in Northants.
Stuck.
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Boka  From North America
Possibilities, orphans and chains (and small chains within larger chains). Not easy.
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Paul  From Canada
-p-o but no nada today. I made an addition error that required a correction but I think nada is there. The 89 crosses solve a lot.
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K S Pavan Kumar  From Hyderabad, India
Lucky solved on first attempt.
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LEAS4U  From Dallas
2:55 I am with KS on this one. Guessed that 21D was a straight 1-6 and there wasn't much left to figure out besides the 8's& 9's.
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Mike  From Los Angeles
Nada. You can prove that C=1. The only other choice is W, which makes 23A = 9851, which doesn't work. Then, 2, 3 & 4 in 6D are forced and the rest is easy.
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Don  From Dallas, TX
thanks Mike for your guess free approach! W=1 was not long chain like I thought (problem with 6 in 21D). I like your approach better than my 5-step -o-g-c. Here was my key step to solve 1 in 21D:
(After solving 7 in 24D,) Regardless of X, solve CD:
a. if X>=8: TSV=547, WZ contains 24, CD=17
b. if X<=7: LP contains 89, KGCD=3217
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willo  From ny
10:24
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willo  From ny
I'm sure I'm being dense but I don't see how Mike rules out W=1. In what sense does 23A=9851 'not work'? And why not 23A=9761 ?
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Don  From Dallas
I can't answer Willo's questions, but consider W=1, TS=45, LP contains 89 (but can't solve 6 in 21D)
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Joe  From NY
+p-o, good puzzle
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Luca  From Lisbon
Agree with Mike and Don
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Aspie  From Mars
Believe it or not it's a nada

All about 89 pairs. P and X can't make an 89 pair together because that makes a 6 cell non unique chain with the two lower 18Ds. Which means L must be the other 89.
Then 20A=389 and easy onwards ...
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willo  From ny
Don: I apologize for my denseness but I still don't follow. We are trying to rule out 1 in W, so we assume 1 in W. Now you say 'consider W=1, TS=45'. But we could equally well consider W=1, S=3, T=6. So W=1 has (at least) two subcases. You are trying to rule out one of those subcases, but what about the other one?
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willo  From ny
Don: Or perhaps my denseness was of a different form. I had thought you were claiming that we could automatically rule out the other case, but I see now that you appear to have been claiming nothing of the kind.
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Ross  From Murchison, Vic
4:17
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Anna  From QLD, Australia
7:01
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Dan  From L.A.
Seemed straightforward +p +o. Key for me was seeing C + D = 8 and G + H = 8, but that if you only used 2/3 in C and G, 5 & 6 in D & H, you wouldn't have a unique solution. So that forced C=1, D=7.
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Jimmy  From Scotland
Long chain to prove Aspie's 89 uniqueness, 2021.
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